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9z^2-44z-5=0
a = 9; b = -44; c = -5;
Δ = b2-4ac
Δ = -442-4·9·(-5)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-46}{2*9}=\frac{-2}{18} =-1/9 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+46}{2*9}=\frac{90}{18} =5 $
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